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AIEEE 2003 Physics Solved Paper
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© examsnet.com
Question : 4
Total: 74
A boy playing on the roof of a
10
m
high building throws a ball with a speed of
10
m
/
s
at an angle of
30
∘
with the horizontal. How far from the throwing point will the ball be at the height of
10
m
from the ground?
[
g
=
10
m
/
s
2
,
s
i
n
30
∘
=
1
2
,
cos
30
∘
=
√
3
2
]
5.20
m
4.33
m
2.60
m
8.66
m
Validate
Solution:
From the figure it is clear that maximum horizontal range
R
=
u
2
s
i
n
2
θ
g
=
(
10
)
2
s
i
n
(
2
×
30
∘
)
10
=
5
√
3
=
8.66
m
© examsnet.com
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