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AIEEE 2003 Physics Solved Paper
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© examsnet.com
Question : 43
Total: 74
The length of a wire of a potentiometer is
100
cm
, and the
e
.
m
.
f
. of its standard cell is
E
volt. It is employed to measure the
e
.
m
.
f
. of a battery whose internal resistance in
0.5
Ω
. If the balance point is obtained at
1
=
30
cm
from the positive end, the
e
.
m
.
f
. of the battery is
where
i
is the current in the potentiometer wire.
30
E
100.5
30
E
(
100
−
0.5
)
30
(
E
−
0.5
i
)
100
30
E
100
−
0.5
i
, where
i
is the current in the potentiometer wire
Validate
Solution:
Potential gradient along wire,
K
=
E
100
volt/cm
For battery
V
=
E
′
- ir, where
E
′
is emf of battery.
or
K
×
30
=
E
′
−
ir
, where current
i
is drawn from battery
or
E
×
30
100
=
E
′
+
0.5
i
or
E
′
=
30
E
100
−
0.5
i
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