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AIEEE 2004 Math Solved Paper
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© examsnet.com
Question : 42
Total: 68
The value of
I
=
π
∕
2
∫
0
(
s
i
n
x
+
cos
x
)
2
√
1
+
s
i
n
2
x
dx
is
3
1
2
0
Validate
Solution:
I
=
π
2
∫
0
(
s
i
n
x
+
cos
x
)
2
√
1
+
s
i
n
2
x
dx
We know
[
(
s
i
n
x
+
cos
x
)
2
=
1
+
s
i
n
2
x
]
, So
I
=
π
2
∫
0
(
s
i
n
x
+
cos
x
)
2
(
s
i
n
x
+
cos
x
)
dx
=
π
2
∫
0
(
s
i
n
x
+
cos
x
)
dx
[
s
i
n
x
+
cos
x
>
0.
if
0
<
x
<
π
2
]
or
I
=
[
−
cos
x
+
s
i
n
x
]
0
π
2
=
−
cos
π
2
+
s
i
n
π
2
+
cos
0
−
s
i
n
0
=
−
0
+
1
+
1
−
0
=
2
© examsnet.com
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