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AIEEE 2004 Physics Solved Paper
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© examsnet.com
Question : 31
Total: 78
A particle at the end of a spring executes
S
.
H
.
M
with a period
t
1
. While the corresponding period for another spring is
t
2
. If the period of oscillation with the two springs in series is
T
then
T
−
1
=
t
1
−
1
+
t
2
−
1
T
2
=
t
1
2
+
t
2
2
T
=
t
1
+
t
2
T
−
2
=
t
1
−
2
+
t
2
−
2
Validate
Solution:
For first spring,
t
1
=
2
π
√
m
k
1
,
For second spring,
t
2
=
2
π
√
m
k
2
when springs are in series then,
k
e
f
f
=
k
1
k
2
k
1
+
k
2
∴
T
=
2
π
√
m
(
k
1
+
k
2
)
k
1
k
2
∴
T
=
2
π
√
m
k
2
+
m
k
1
=
2
π
√
t
2
2
(
2
π
)
2
+
t
1
2
(
2
π
)
2
⇒
T
2
=
t
1
2
+
t
2
2
© examsnet.com
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