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AIEEE 2004 Physics Solved Paper
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© examsnet.com
Question : 52
Total: 78
A long wire carries a steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is
B
. It is then bent into a circular loop of
n
turns. The magnetic field at the center of the coil will be
2
n
B
n
2
B
n
B
2
n
2
B
Validate
Solution:
KEY CONCEPT : Magnetic field at the center of a circular coil of radius
R
carrying
current is
B
=
µ
0
i
2
R
Given:
n
×
(
2
π
r
′
)
=
2
π
R
⇒
n
r
′
=
R
B
′
=
n
⋅
µ
0
i
2
r
′
from (1) and (2),
B
′
=
n
µ
0
i
⋅
n
2
π
R
=
n
2
B
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