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AIEEE 2004 Physics Solved Paper
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© examsnet.com
Question : 71
Total: 78
The binding energy per nucleon of deuteron
(
1
2
H
)
and helium nucleus
(
2
4
H
e
)
is
1.1
MeV
and
7
MeV
respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is
23.6
MeV
26.9
MeV
13.9
MeV
19.2
MeV
Validate
Solution:
The nuclear reaction of process is
2
1
2
H
→
4
2
He
Energy released
=
4
×
(
7
)
−
4
(
1.1
)
=
23.6
MeV
© examsnet.com
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