Let {a}↖{→}={i}↖{∧}-{k}↖{∧}, {b}↖{→}=x {i}↖{∧}+{j}↖{∧}+(1-x) {k}↖{∧} and {c}↖{→}=y {i}↖{∧}+x {j}↖{∧}+(1+x-y) {k}↖{∧}. Then [{a}↖{→}, {b}↖{→}, {c}↖{→}] depends on

Question

Examsnet · Accepted Answer

Correct Answer is : neither x nor y

1	0	−1
x	1	1−x
y	x	1+x−y

AIEEE 2005 Math Solved Paper