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AIEEE 2005 Physics Solved Paper
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© examsnet.com
Question : 12
Total: 74
A spherical ball of mass
20
kg
is stationary at the top of a hill of height
100
m
. It rolls down a smooth surface to the ground, then climbs up another hill of height
30
m
and finally rolls down to a horizontal base at a height of
20
m
above the ground. The velocity attained by the ball is
20
m/s
40
m/s
10
√
30
m/s
10
m/s
Validate
Solution:
Loss in potential energy
=
gain in kinetic energy
m
×
g
×
80
=
1
2
m
v
2
⇒
10
×
80
=
1
2
v
2
⇒
v
2
=
1600
or
v
=
40
m
/
s
© examsnet.com
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