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AIEEE 2005 Physics Solved Paper
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© examsnet.com
Question : 5
Total: 74
A bullet fired into a fixed target loses half of its velocity after penetrating
3
cm
. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?
2.0
cm
3.0
cm
1.0
cm
1.5
cm
Validate
Solution:
Let
K
be the initial kinetic energy and
F
be the resistive force. Then according to work energy theorem,
W
=
∆
K
i.e.,
3
F
=
1
2
m
v
2
−
1
2
m
(
v
2
)
2
......(i)
Let the bullet will penetrate
x
cm
more before coming to rest.
∴
F
x
=
1
2
m
(
v
2
)
2
−
1
2
m
(
0
)
2
.......(ii)
Dividing eq. (i) and (ii) we get,
x
3
=
1
3
or
x
=
1
cm
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