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AIEEE 2005 Physics Solved Paper
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© examsnet.com
Question : 8
Total: 74
Consider a car moving on a straight road with a speed of
100
m
∕
s
. The distance at which car can be stopped is
[
µ
k
=
0.5
]
1000
m
800
m
400
m
100
m
Validate
Solution:
Acceleration due to friction
=
(
−
µ
k
g
)
We know,
v
2
=
u
2
+
2
a
s
⇒
0
2
=
u
2
+
2
(
−
µ
k
g
)
s
⇒
2
µ
k
g
s
=
u
2
⇒
s
=
100
2
2
×
0.5
×
10
⇒
s
=
1000
m
© examsnet.com
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