(i) Ag→Ag++e− E∘=−0.800V (ii) Ag+I−→AgI+e− E∘=0.152V From (i) and (ii) we have, ‌AgI→Ag++I− ‌‌‌‌‌E∘=−0.952V ‌E‌cell ‌∘=‌
0.059
n
‌log‌K ‌∴−0.952=‌
0.059
1
‌log[Ag+][I−] ‌‌[ as ‌k=[Ag+][I−] ‌ or ‌−‌