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AIEEE 2006 Solved Paper
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© examsnet.com
Question : 1
Total: 143
How many moles of magnesium phosphate
Mg
3
(
PO
4
)
2
will contain
0.25
mole of oxygen atoms?
1.25
×
10
−
2
2.5
×
10
−
2
0.02
3.125
×
10
−
2
Validate
Solution:
In one
Mg
3
(
PO
4
)
2
molecule no of oxygen atoms
=
8
So if there is
M
mole of
Mg
3
(
PO
4
)
2
molecules then no of moles of oxygen atoms is
=
M
×
8
According to question,
M
×
8
=
0.25
⇒
M
=
0.03125
=
3.125
×
10
−
2
© examsnet.com
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