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AIEEE 2006 Solved Paper
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© examsnet.com
Question : 120
Total: 143
Let
a
1
,
a
2
,
a
3
.
.
.
. be terms on A.P. If
a
1
+
a
2
+
.
.
.
.
.
.
a
p
a
1
+
a
2
+
.
.
.
a
q
=
p
2
q
2
,
p
≠
q
, then
a
6
a
21
equals
41
11
7
2
2
7
11
41
Validate
Solution:
p
2
[
2
a
1
+
(
p
−
1
)
d
]
q
2
[
2
a
1
+
(
q
−
1
)
d
]
=
p
2
q
2
⇒
2
a
1
+
(
p
−
1
)
d
2
a
1
+
(
p
−
1
)
d
=
p
q
a
1
+
(
p
−
1
2
)
d
a
1
+
(
q
−
1
2
)
d
=
p
q
For
a
6
a
21
,
p
=
11
,
q
=
41
⇒
a
6
a
21
=
11
41
© examsnet.com
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