The enthalpy changes for the following processes are listed below:
‌Cl2(g)=2‌Cl(g),242.3‌kJ‌mol−1
‌I2(g)=2I(g),151.0‌kJ‌mol−1
‌ICl(g)=I(g)+Cl(g),211.3‌kJ‌mol−1
‌I2( s)=I2(g),62.76‌kJ‌mol−1
Given that the standard states for iodine and chlorine are I2( s) and Cl2(g), the standard enthalpy of formation for ICl(g) is

Question

Examsnet · Accepted Answer

Correct Answer is : +16.8‌kJ‌mol−1

AIEEE 2006 Solved Paper