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AIEEE 2006 Solved Paper
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© examsnet.com
Question : 35
Total: 143
The "spin-only" magnetic moment [in units of Bohr magneton,
(
µ
B
)
D
"
Ni
2
+
in aqueous solution would be (Atomic number of
Ni
=
28
)
2.84
4.90
0
1.73
Validate
Solution:
The number of unpaired electrons in
N
i
2
+
(
a
q
)
=
2
Water is weak ligand hence no pairing will take place spin magnetic moment
=
√
n
(
n
+
2
)
=
√
2
(
2
+
2
)
=
√
8
=
2.82
© examsnet.com
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