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AIEEE 2006 Solved Paper
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© examsnet.com
Question : 63
Total: 143
A bomb of mass
16
kg
at rest explodes into two pieces of masses
4
kg
and
12
kg
. The velocity of the
12
kg
mass is
4
ms
−
1
. The kinetic energy of the other mass is
144 J
288 J
192 J
96 J
Validate
Solution:
Here linear momentum is conserved as no external force is acting on the bomb.
Let the velocity and mass of
4
kg
piece be
v
1
and
m
1
and that of
12
kg
piece be
v
2
and
m
2
Applying conservation of linear momentum
0
=
m
2
v
2
−
m
1
v
1
⇒
v
1
=
12
×
14
4
=
12
m
s
−
1
∴
K
.
E
1
=
1
2
m
1
v
1
2
=
1
2
×
4
×
144
=
288
J
© examsnet.com
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