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AIEEE 2007 Solved Paper
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© examsnet.com
Question : 113
Total: 118
Let
→
a
=
∧
i
+
∧
j
+
∧
k
,
→
b
=
∧
i
−
∧
j
+
2
∧
k
and
→
c
=
x
∧
i
+
(
x
−
2
)
∧
i
−
∧
k
. If the vectors
→
c
lies in the plane of
→
a
and
→
b
, then
x
equals
−
4
−
2
0
1
Validate
Solution:
Given
→
a
=
∧
i
+
∧
j
+
∧
k
,
→
b
=
∧
i
−
∧
j
+
2
∧
k
and
→
c
=
x
∧
i
+
(
x
−
2
)
∧
j
−
∧
k
If
→
c
lies in the plane of
→
a
and
→
b
then
[
→
a
→
b
→
c
]
=
0
i.e.
|
1
1
1
1
−
1
2
x
(
x
−
2
)
−
1
|
=
0
⇒
1
[
1
−
2
(
x
−
2
)
]
−
1
[
−
1
−
2
x
]
+
1
[
x
−
2
+
x
]
=
0
⇒
1
−
2
x
+
4
+
1
+
2
x
+
2
x
−
2
=
0
⇒
2
x
=
−
4
⇒
x
=
−
2
© examsnet.com
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