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AIEEE 2007 Solved Paper
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© examsnet.com
Question : 44
Total: 118
A
2
kg
block slides on a horizontal floor with a speed of
4
m
/
s
. It strikes a uncompressed spring, and compress it till the block is motionless. The kinetic friction force is
15
N
and spring constant is
10
,
000
N
/
m
. The spring compresses by
8.5
cm
5.5
cm
2.5
cm
11.0
cm
Validate
Solution:
Let the block compress the spring by
x
before coming to rest.
Initial kinetic energy of the block
=
(potential energy of compressed spring)
+
work done due to friction.
1
2
×
2
×
(
4
)
2
=
1
2
×
10000
×
x
2
+
15
×
x
10
,
000
x
2
+
30
x
−
32
=
0
⇒
5000
x
2
+
15
x
−
16
=
0
∴
x
=
−
15
±
√
(
15
)
2
−
4
×
(
5000
)
(
−
16
)
2
×
5000
=
0.055
m
=
5.5
cm
© examsnet.com
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