Examsnet
Unconfined exams practice
Home
Exams
Banking Entrance Exams
CUET Exam Papers
Defence Exams
Engineering Exams
Finance Entrance Exams
GATE Exam Practice
Insurance Exams
International Exams
JEE Exams
LAW Entrance Exams
MBA Entrance Exams
MCA Entrance Exams
Medical Entrance Exams
Other Entrance Exams
Police Exams
Public Service Commission (PSC)
RRB Entrance Exams
SSC Exams
State Govt Exams
Subjectwise Practice
Teacher Exams
SET Exams(State Eligibility Test)
UPSC Entrance Exams
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Careers
Contact Us
Our Apps
Privacy
Test Index
AIEEE 2007 Solved Paper
Show Para
Hide Para
Share question:
© examsnet.com
Question : 69
Total: 118
Two identical conducting wires
A
O
B
and
C
O
D
are placed at right angles to each other. The wire
A
O
B
carries an electric current
I
1
and
C
O
D
carries a current
I
2
. The magnetic field on a point lying at a distance
d
from
O
, in a direction perpendicular to the plane of the wires
A
O
B
and
C
O
D
, will be given by
µ
0
2
π
d
(
I
1
2
+
I
2
2
)
µ
0
2
π
(
I
1
+
I
2
d
)
1
2
µ
0
2
π
d
(
I
1
2
+
I
2
2
)
1
2
µ
0
2
π
d
(
I
1
+
I
2
)
Validate
Solution:
Clearly, the magnetic fields at a point
P
, equidistant from
A
O
B
and
C
O
D
will have directions perpendicular to each other, as they are placed normal to each other.
∴
Resultant field,
B
=
√
B
1
2
+
B
2
2
But
B
1
=
µ
0
I
1
2
π
d
and
B
2
=
µ
0
I
2
2
π
d
∴
B
=
√
(
µ
0
2
π
d
)
2
(
I
1
2
+
I
2
2
)
or,
B
=
µ
0
2
π
d
(
I
1
2
+
I
2
2
)
1
/
2
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
Prev Question
Next Question