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AIEEE 2007 Solved Paper
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© examsnet.com
Question : 77
Total: 118
The half-life period of a ratio-active element
X
is same as the mean life time of another ratio-active element
Y
. Initially they have the same number of atoms. Then
X
and
Y
decay at same rate always
X
will decay faster than
Y
Y
will decay faster than
X
X
and
Y
have same decay rate initially
Validate
Solution:
According to question,
Half life of
X
,
T
1
∕
2
=
τ
a
v
, average life of
Y
⇒
0.693
λ
X
=
1
λ
Y
⇒
λ
X
=
(
0.693
)
⋅
λ
Y
∴
λ
X
<
λ
Y
Now, the rate of decay is given by
−
d
N
d
t
=
λ
N
∴
Y
will decay faster than
X
. [ as
N
is same ]
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