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AIEEE 2008 Solved Paper
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© examsnet.com
Question : 26
Total: 104
The coordination number and the oxidation state of the element '
E
' in the complex
[
E
(
en
)
2
(
C
2
O
4
)
]
NO
2
(where (en) is ethylene diamine) are, respectively,
6 and 2
4 and 2
4 and 3
6 and 3
Validate
Solution:
In the given complex we have two bidentate ligands (i.e. en and
C
2
O
4
), so coordination number of
E
is
6
(
2
×
2
+
1
×
2
=
6
)
Let the oxidation state of
E
in complex be
x
,
then
[
x
+
(
−
2
)
=
1
]
or
x
−
2
=
1
or
x
=
+
3
, so its oxidation state is
+
3
© examsnet.com
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