Number of electron in NO+=number of electron in CN−=14 electrons. As both have same number of electrons so their bond order is equal. Moleculer orbital configuration of NO+(14 electrons) is
=σ1s2σ1s2*σ2s2σ2s2*σ2pz2π2pz2=π2py2π2px0*=π2py0*
∴B.0=
1
2
[10−4]=3 Moleculer orbital configuration of CN−(14 electrons) is =σ1s2σ1s2*σ2s2σ2s2*π2px2=π2py2σ2pz2 ∴B.0=