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AIEEE 2008 Solved Paper
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© examsnet.com
Question : 44
Total: 104
A planet in a density solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is
11
km
s
−
1
, the escape velocity from the surface of the planet would be
1.1
km
s
−
1
100
km
s
−
1
110
km
s
−
1
0.11
km
s
−
1
Validate
Solution:
Let
M
e
is mass of earth then mass of planet
M
p
=
10
M
e
.
And let
R
e
is radius of earth then radius of planet
R
p
=
R
c
10
Escape velocity of earth,
v
e
=
√
2
G
M
e
R
e
Escape velocity of planet,
v
p
=
√
2
G
M
p
R
p
∴
v
p
v
e
=
√
2
G
M
p
R
p
√
2
G
M
e
R
e
=
√
M
p
M
e
×
R
e
R
p
=
√
10
M
e
M
e
×
R
e
R
e
∕
10
=
10
∴
v
p
=
10
×
v
e
=
10
×
11
=
110
km
∕
s
© examsnet.com
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