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AIEEE 2009 Solved Paper
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© examsnet.com
Question : 49
Total: 89
A current loop
A
B
C
D
is held fixed on the plane of the paper as shown in the figure. The arcs
B
C
(radius
=
b
) and
D
A
(radius
=
a
) of the loop are joined by two straight wires
A
B
and
C
D
. A steady current
I
is flowing in the loop. Angle made by
A
B
and
C
D
at the origin
O
is
30
∘
. Another straight thin wire steady current
I
1
flowing out of the plane of the paper is kept at the origin.
Due to the presence of the current
I
1
at the origin:
The forces on
A
D
are
B
C
are zero.
The magnitude of the net force on the loop is given by
I
1
I
4
π
µ
0
[
2
(
b
−
a
)
+
π
∕
3
(
a
+
b
)
]
.
The magnitude of the net force on the loop is given by
µ
0
I
I
1
24
a
b
(
b
−
a
)
.
The forces on
A
B
and
D
C
are zero.
Validate
Solution:
→
F
=
I
(
→
ℓ
×
→
B
)
The force on
A
D
and
B
C
due to current
I
1
is zero. This is because the directions of current element
→
I
d
ℓ
and magnetic field
→
B
are parallel.
© examsnet.com
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