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AIEEE 2009 Solved Paper
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© examsnet.com
Question : 53
Total: 89
A transparent solid cylindrical rod has a refractive index of
2
√
3
. It is surrounded by air. A light ray is incident at the mid-point of one end of the rod as shown in the figure.
The incident angle
θ
for which the light ray grazes along the wall of the rod is :
sin
−
1
(
√
3
/
2
)
sin
−
1
(
2
/
√
3
)
sin
−
1
(
1
√
3
)
sin
−
1
(
1
/
2
)
Validate
Solution:
Applying Snell's law at
Q
n
=
sin
90
∘
sin
C
=
1
s
i
n
C
∴
sin
C
=
1
n
=
√
3
2
∴
C
=
60
∘
Applying Snell's Law at
P
n
=
sin
θ
sin
(
90
−
C
)
⇒
sin
θ
=
n
×
sin
(
90
−
C
)
;
from (1)
⇒
sin
θ
=
n
cos
∴
θ
=
sin
−
1
[
2
√
3
×
cos
60
0
]
or,
θ
=
s
i
n
−
1
(
1
√
3
)
© examsnet.com
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