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AIEEE 2009 Solved Paper
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© examsnet.com
Question : 81
Total: 89
One ticket is selected at random from 50 tickets numbered
00
,
01
,
02
,
.
.
.
,
49
. Then the probability that the sum of the digits on the selected ticket is 8 , given that the product of these digits is zero, equals:
1
7
5
14
1
50
1
14
Validate
Solution:
Sample space
=
{
00
,
01
,
02
,
03
,
49
}
=
50
tickets
n
(
S
)
=
50
n
(
Sum
=
8
)
=
{
08
,
17
,
26
,
35
,
44
}
=
5
n
(
Product
=
0
)
=
{
00
,
01
,
02
,
03
,
04
,
05
,
06
,
07
,
08
,
09
,
10
,
20
,
30
,
40
}
=
14
∴
Probability when product is
0
=
P
(
Product
=
0
)
=
14
50
n
(
Sum
=
8
∩
Product
=
0
)
=
{
08
}
=
1
∴
Probability when sum is 8 and product is
0
=
P
(
Sum
=
8
∩
Product
=
0
)
=
1
50
Required probability,
P
(
Sum
=
8
Product
=
0
)
=
P
(
Sum
=
8
∩
Product
=
0
)
P
(
Product
=
0
)
=
1
50
14
50
=
1
14
© examsnet.com
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