Examsnet
Unconfined exams practice
Home
Exams
Banking Entrance Exams
CUET Exam Papers
Defence Exams
Engineering Exams
Finance Entrance Exams
GATE Exam Practice
Insurance Exams
International Exams
JEE Exams
LAW Entrance Exams
MBA Entrance Exams
MCA Entrance Exams
Medical Entrance Exams
Other Entrance Exams
Police Exams
Public Service Commission (PSC)
RRB Entrance Exams
SSC Exams
State Govt Exams
Subjectwise Practice
Teacher Exams
SET Exams(State Eligibility Test)
UPSC Entrance Exams
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Careers
Contact Us
Our Apps
Privacy
Test Index
AIEEE 2011 Solved Paper
Show Para
Hide Para
Share question:
© examsnet.com
Question : 36
Total: 91
A mass
m
hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass
m
and radius
R
. Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass
m
, if the string does not slip on the pulley, is:
g
2
3
g
g
3
3
2
g
Validate
Solution:
This is the free body diagram of pulley and mass
For translation motion of the block,
m
g
−
T
=
m
a
For rotational motion of the pulley,
T
×
R
=
I
α
=
I
a
R
where
α
=
angular acceleration of disc
=
a
R
and
I
=
1
2
m
R
2
(For circular disc)
Solving (1) & (2),
a
=
m
g
(
m
+
I
R
2
)
=
m
g
m
+
m
R
2
2
R
2
=
2
m
g
3
m
=
2
g
3
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
Prev Question
Next Question