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AIEEE 2011 Solved Paper
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© examsnet.com
Question : 43
Total: 91
Three perfect gases at absolute temperatures
T
1
,
T
2
and
T
3
are mixed. The masses of molecules are
m
1
,
m
2
and
m
3
and the number of molecules are
n
1
,
n
2
and
n
3
respectively. Assuming no loss of energy, the final temperature of the mixture is:
n
1
T
1
+
n
2
T
2
+
n
3
T
3
n
1
+
n
2
+
n
3
n
1
T
1
2
+
n
2
T
2
2
+
n
3
T
3
2
n
1
T
1
+
n
2
T
2
+
n
3
T
3
n
1
2
T
1
2
+
n
2
2
T
2
2
+
n
3
2
T
3
2
n
1
T
1
+
n
2
T
2
+
n
3
T
3
(
T
1
+
T
2
+
T
3
)
3
Validate
Solution:
Number of moles of first gas
=
n
1
N
A
Number of moles of second gas
=
n
2
N
A
Number of moles of third gas
=
n
3
N
A
If there is no loss of energy then
P
1
V
1
+
P
2
V
2
+
P
3
V
3
=
P
V
n
1
N
A
R
T
1
+
n
2
N
A
R
T
2
+
n
3
N
A
R
T
3
=
n
1
+
n
2
+
n
3
N
A
R
T
m
i
x
⇒
T
mix
=
n
1
T
1
+
n
2
T
2
+
n
3
T
3
n
1
+
n
2
+
n
3
© examsnet.com
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