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AIEEE 2012 Solved Paper
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© examsnet.com
Question : 82
Total: 89
A equation of a plane parallel to the plane
x
−
2
y
+
2
z
−
5
=
0
and at a unit distance from the origin is:
x
−
2
y
+
2
z
−
3
=
0
x
−
2
y
+
2
z
+
1
=
0
x
−
2
y
+
2
z
−
1
=
0
x
−
2
y
+
2
z
+
5
=
0
Validate
Solution:
Given equation of a plane is
x
−
2
y
+
2
z
−
5
=
0
So, Equation of parallel plane is given by
x
−
2
y
+
2
z
+
d
=
0
Now, it is given that distance from origin to the parallel planes is 1 .
∴
|
d
√
1
2
+
2
2
+
2
3
|
=
1
⇒
d
=
±
3
So equation of required plane
x
−
2
y
+
2
z
±
3
=
0
© examsnet.com
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