[−(t+5)−2] =2(t+5)−3 ...(iii) From equation (ii), we get v3/2=−(t+5)−3....(iv) Substituting this in equation (iii) we get Acceleration, a=−2v3/2 or a ∝( velocity )3/2 From equation (i), we get x3=(t+5)−3 Substituting this in equation (iii), we get Acceleration, a=2x3 or a∝( distance )3