According to given figure, Applying KVL in loop (i) 500I1+R(I1−I2)=12 (500+R)I1−RI2=12 .........(i) Applying KVL in loop (ii), we have R(I2−I1)=−2 RI2=RI1−2 .........(ii) From Eqs. (i) and (ii), we get (500+R)I1−(RI1−2)=12 500I1+RI1−RI1+2=12 500I1=10 I1=
1
50
From Eq. (ii), RI2=R×
1
50
−2 But given that galvanometer G shows zero deflection, hence I2=0. ∴ 0=