Solution:
Given that, Y={1,2,3,4,5}
A={1,2}
B={3,4,5}
∴(Y×A)={(1,1),(1,2),(2,1),(2,2)
(3,1),(3,2)(4,1),(4,2),(5,1),(5,2)}
and(Y×B)={(1,3),(1,4),(1,5),(2,3)
(2,4),(2,5),(3,3),(3,4),(3,5),(4,3)
(4,4),(4,5),(5,3),(5,4),(5,5)}
Now, (Y×A)∩(Y×B)=ϕ(null set)
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