y 2 > 2 , then Options: x 2 ≤ 2 x 2 < 2 2" class="fm-inline"> x 2 > 2 x 2 ≥ 2 Solution: Given that, x = [ a + 2 b a + b ] and y = a b ∴ x = a + 2 b a + b = a b + 2 1 + a b = 1 + 1 a b + 1 ⇒ x = 1 + 1 y + 1 2 (\given) ]" class="fm-inline"> [ ∵ y = a b and y 2 > 2 ( given ) ] which shows x 2 < 2 ." >
