Given R1=44Ω R2=36Ω\XL=90Ω XC=30Ω Total resistance of the circuit is R‌‌=R1+R2 ‌‌=44+36=80Ω Impedance ofthe circuit, Z=√R2+(XL−XC)2 ⇒‌‌Z=√(80)2+(60)2 ⇒‌‌Z=√6400+3600=100Ω ‌ Current, ‌I=‌
V
Z
=‌
200
100
=2A Power dissipated in the coil, Pav=I2R =(2)2×80=320watt