As,∆Q‌‌=Q1+Q2+Q3+Q4 ‌‌=5960−5585−2980+3645 ‌‌=1040J Also, ∆W‌‌=W1+W2+W3+W4 ‌‌=2200−825−1100+W4 ‌‌=275+W4 For a cyclic process,∆U=0 i.e., ‌‌Uf−Ui=0, From first law of thermodynamics, ∆Q‌‌=∆U+∆W 1040‌‌=0+275+W4‌ or ‌W4=765J