f1(x)=x2−x+1,f2(x)=x3−x2−2x+1⇒f11(x)=2x−1,f21(x)=3x2−2x−2Let the tangents drawn to the curvey=f1(x);y=f2(x)At(x1,y1);(x2,y2) are parallel⇒2x1−1=3x22−2x2−2⇒2x1=3x22−2x2−1Which is possible for infinite numbers of ordered pairs⇒ Infinite solutions