At a given temperature, when ionic product (Kip ) over comes solubility product (Ksp), precipitation of the sparingly soluble electrolyte (here, it is CaF2 ) takes place.
Kip=[Ca2+][F−]2=(10−2)(10−5)2=10−12<Ksp
=1.6×10−10 So, at this condition (10−2MCa2++10−3MF−). precipitation of CaF2 will not occur.