The free body diagram of the system is sown below,
The acceleration of the block is, a=µg a=(0.2)(10) a=2m∕s2 The initial velocity of the block is calculated as v2=u2−2as (0)2‌‌=u2−2(2)(1) u‌‌=2m∕s The net accelerating force down the inclined plane is, F‌‌=ma1 mg‌sin‌30∘−µmg‌cos‌30∘‌‌=ma1 a1‌‌=g(sin‌30∘−µ‌cos‌30∘) a1‌‌=5(1−√3µ) The displacement is calculated as v12‌‌=u12+2a1S (2)2‌‌=(0)2+2[5(1−√3µ)]S‌( As, ‌v1=u=2m∕s,u1=0) S‌‌=‌
2
5(1−√3µ)
S‌‌=0.612m The work done by friction force is, W=(µmg‌cos‌30∘)S+‌