Let m1 and m2 be the slopes of lines. Then, m1+m2= arithmetic mean =
13
2
.....(i) and m1m2= geometric mean =√36=6 .....(ii) Now, equation of the pair of lines passing through the origin is (y−m1x)(y−m2x)=0 ⇒y2−(m1+m2)xy+m1m2x2=0 Using Eq. (i) and (ii), we get y2−