It is given.
=+ + x2+5x+7=A(x−3)2 +B(x−3)+C ......(I)
Substituting the value of
x as 3 in above equation we get.
C=9+15+7=31 Substituting the value of
x as 0 in above equation we get,
9A−3B+31=7 3A−B=−8 Substituting the value of
x as 1 in above equation we get,
4A−2B+31=1+5+7 2A−B=−9 Pn solving the above two to obtain the value of
A and
B.
A=1 and
B=11 The equation of line having slope
A and passing through the point
(B,C) is,
y−31=1(x−11) y−31=x−11 x−y+20=0