AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper

The displacement of a hanging block is given by,
s=ut+

1

2

at2
Here, displacement is 2 m.
2=0(t)+

1

2

a(2)2
2=2a
a=1ms−2
So, the velocity of a 10 kg block after 2 s is equal to the velocity of a hanging block.
v=u+at
=0+1×2
=2ms−1
By using work energy theorem the total work done by a hanging block due to gravity is equal to the kinetic energy of a 10 kg block.

1

2

(10)(2)2=m(10)(2)
m=1‌kg
So, the weight of a hanging block is,
Wblock=(1‌kg)×(10ms−2)
=(10‌kg.m∕s2)
=10N
≈11.11N