=r Then, point on above line is p(2r+1,1−r). Now the equation of the plane passing through (2
^
i
+4
^
j
) andparallel to the vector (3
^
j
+5
^
k
) and (3
^
i
−
^
k
) in Cartesian form is, |
x−2
y−4
z
0
3
5
3
0
−1
|=0 −3(x−2)+15(y−4)−9z=0 3x−15y+9z+54=0 Let the point p(2r+1,1−r) on the above plane itself then, r=14 So, the position vector of point P is, OP=29