From the graph, centre of circle is (2, 0) and radius is 2. The equation of the circle is, (s−2)2+(v−0)2=22 (s−2)2+v2=4 Differentiate above equation with respect to time, 2(s−2)
ds
dt
+2v
dv
dt
=0 2(s−2)v+2va=0 Apply the condition; at s=2−√2.v=√2 2(2−√2−2)×√2+2√2a=0 a=