Given equation of pair is 3x2−5xy+2y2=0 (3x−2y)(x−y)=0 The equation of the two sides of the triangle is 3x−2y=0 x−y=0 The line 2x+3y+k=0 passes through the point (2,1) 4+3+k=0 k=−7 Therefore, 2x+3y−7=0 The point of intersection of line y−x=0 and 2x+3y−7=0 is x=
7
5
,y=
7
5
The line x+y+k=0 passes through the point (2,1). 2+1+k−0 k=−3 The point of intersection of line x+y−3 and 3x−2y=0 isx=
6
5
,y=
9
5
The equation of the third side of the triangle is y−