Calculate the Normality of H2O2 Normality of H2O2=
Volume strength
Equivalent weight
=
20
5.6
=3.57N The reaction is in acidic mediumfor KMnO4 so, valence factor will be 5 The normality of KMnO4 is, NKMnO4= Molarity ×5 Use the following expression. N1V1(H2O2)=N2V2(KMnO4) Substitute thevalues. 3.57×V1=0.02×5×500 V1=