The solution is given as, y=A(x)e−∫Pdx The above equation is linear differential equation. The integral factor is, IF=e∫P(x)dx The solution is, y(IF)=∫Q(x)×IFdx ye∫P(x)dx=∫Q(x)e∫P(x)dxdx Substitute the values in the above equation from given expression A(x)=∫Q(x)e∫P(x)dxdx A′(x)=Q(x)e∫P(x)dx