By the method of verification if k = 0 , 2.41+31=11t 8+3=11t t=1 Now, from the second given relation on putting the values of (k,t)=(0,1), we get 2.(64)+81=11(p+39) 128+81=11(p+39) 11(p+39)=209 p+3q=19 From the option p must be 16 and q = 1 . So, (3k+1)k=0