acosA=bcosBa(2bcb2+c2−a2)=b(2aca2+c2−b2)⇒ba(b2+c2−a2)=ab(a2+c2−b2)⇒a2(b2+c2−a2)=b2(a2+c2−b2)⇒a2b2+a2c2−a4=a2b2+b2c2−b4⇒a4−b4+b2c2−a2c2=0⇒(a2−b2)(a2+b2)+c2(b2−a2)=0⇒(a2−b2)[a2+b2−c2]=0 As (a=b),a2−b2=0a2+b2−c2=0⇒a2+b2=c2∴△ABC is a right angled triangle with AB as hypotenuse.