Total number of ways =[ Number of ways in which ₹10 can be distributed among three people] - [Number of ways A can have more than ₹ 6] [Number of ways B can have more than ₹ 7] [Number of ways C can have more than ₹ 8] Total possibilities =(n+r−1)Cn=(10+3−1)C10=12C10=
12!
10!2!
=66 A can have more than 6 in 5C3=10 ways B can have more than 7 in 4C2=6 ways C can have more than 8 in 3C1=3 ways ∴ Total number of ways =66−10−6−3=47