Given that, P(A)=0.6 and P(B)=0.8 ⇒P(A′)=0.4 and (P(B′)=0.2. ∴ Probability that Awins=P(A)+P(A′)P(B′)P(A)+P(A′)P(B′)P(A′)P(B′)P(A)+... ⇒P(A wins )=0.6+(0.4)(0.2)(0.6)+(0.4)2(0.2)2(0.6)+.... ⇒P(A wins )=
0.6
1−(0.4×0.2)
[above series is an infinite GP series with a=0.6 and r=0.4×0.2 ⇒P(A wins )=